A right triangle with sides 6 , cm, 8 , cm an | vedclass

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Question

(A) When a right triangle with sides $6 \, cm, 8 \, cm$ and $10 \, cm$ is revolved about the side $8 \, cm$,the side $8 \, cm$ becomes the height $(h)

Vedclass · Accepted Answer

$301.44 \, cm^3, 188.4 \, cm^2$

Vedclass · Answer

(A) When a right triangle with sides $6 \, cm, 8 \, cm$ and $10 \, cm$ is revolved about the side $8 \, cm$,the side $8 \, cm$ becomes the height $(h)$ of the cone,and the side $6 \, cm$ becomes the radius $(r)$ of the base. The hypotenuse $10 \, cm$ becomes the slant height $(l)$ of the cone.Given: $r = 6 \, cm, h = 8 \, cm, l = 10 \, cm$.Volume of the cone $V = \frac{1}{3} \pi r^2 h = \frac{1}{3} 	imes 3.14 	imes (6)^2 	imes 8 = \frac{1}{3} 	imes 3.14 	imes 36 	imes 8 = 3.14 	imes 12 	imes 8 = 301.44 \, cm^3$.Curved surface area of the cone $CSA = \pi r l = 3.14 	imes 6 	imes 10 = 188.4 \, cm^2$.

$A$ right triangle with sides $6 \, cm, 8 \, cm$ and $10 \, cm$ is revolved about the side $8 \, cm$. Find the volume and curved surface area of the cone so formed. $(\pi = 3.14)$

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