A rigid ball of mass m strikes a rigid wall a | vedclass

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(C) The impulse imparted by the wall on the ball is equal to the change in momentum of the ball, $\vec{J} = \Delta \vec{p} = \vec{p}_f - \vec{p}_i$.Le

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$mv$

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(C) The impulse imparted by the wall on the ball is equal to the change in momentum of the ball, $\vec{J} = \Delta \vec{p} = \vec{p}_f - \vec{p}_i$.Let the velocity of the ball be $\vec{v}$. The angle of incidence with the wall is $60^\circ$, so the angle with the normal is $	heta = 90^\circ - 60^\circ = 30^\circ$.The initial momentum is $\vec{p}_i = m(v \sin 30^\circ \hat{i} - v \cos 30^\circ \hat{j})$.The final momentum is $\vec{p}_f = m(-v \sin 30^\circ \hat{i} - v \cos 30^\circ \hat{j})$.The change in momentum is $\Delta \vec{p} = \vec{p}_f - \vec{p}_i = -2mv \sin 30^\circ \hat{i}$.Since $\sin 30^\circ = 0.5$, the magnitude of impulse is $|\vec{J}| = |-2mv(0.5)| = mv$.

$A$ rigid ball of mass $m$ strikes a rigid wall at an angle of $60^\circ$ with the wall surface and gets reflected without loss of speed as shown in the figure. The magnitude of the impulse imparted by the wall on the ball is:

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