A rigid body is rotating with variable angula | vedclass

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(B) The angular velocity is given by $\omega = a - bt$.To find the time $t$ when the body comes to rest,we set $\omega = 0$:$a - bt = 0 \implies t = \

Vedclass · Accepted Answer

$\frac{a^2}{2b}$

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(B) The angular velocity is given by $\omega = a - bt$.To find the time $t$ when the body comes to rest,we set $\omega = 0$:$a - bt = 0 \implies t = \frac{a}{b}$.The angular displacement $	heta$ is the integral of angular velocity with respect to time:$	heta = \int_{0}^{t} \omega \, dt = \int_{0}^{a/b} (a - bt) \, dt$.Integrating the expression:$	heta = \left[ at - \frac{bt^2}{2} ight]_{0}^{a/b}$.Substituting the limits:$	heta = a\left( \frac{a}{b} ight) - \frac{b}{2} \left( \frac{a}{b} ight)^2 = \frac{a^2}{b} - \frac{b a^2}{2b^2} = \frac{a^2}{b} - \frac{a^2}{2b} = \frac{a^2}{2b}$.

$A$ rigid body is rotating with variable angular velocity $\omega = (a - bt)$ at any instant of time $t$. The total angle subtended by it before coming to rest will be ($a$ and $b$ are constants).

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