A road is 10, m wide. Its radius of curvature | vedclass

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(D) For a banked road without friction,the optimum velocity $v$ is given by the formula: $	an 	heta = \frac{v^2}{rg}$.Here,$	an 	heta \approx \sin

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(D) For a banked road without friction,the optimum velocity $v$ is given by the formula: $	an 	heta = \frac{v^2}{rg}$.Here,$	an 	heta \approx \sin 	heta = \frac{h}{l}$,where $h = 1.5\, m$ is the height of the outer edge and $l = 10\, m$ is the width of the road.Equating the two,we get $\frac{v^2}{rg} = \frac{h}{l}$.Rearranging for $v$,we get $v = \sqrt{\frac{rgh}{l}}$.Substituting the given values: $r = 50\, m$,$g = 9.8\, m/s^2$,$h = 1.5\, m$,and $l = 10\, m$.$v = \sqrt{\frac{50 	imes 9.8 	imes 1.5}{10}} = \sqrt{5 	imes 9.8 	imes 1.5} = \sqrt{73.5} \approx 8.57\, m/s$.Thus,the most suitable velocity is approximately $8.5\, m/s$.

$A$ road is $10\, m$ wide. Its radius of curvature is $50\, m$. The outer edge is raised above the inner edge by a distance of $1.5\, m$. This road is most suited for the velocity .......... $m/s$. (in $.5$)

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