A rod (AB) is attached to a fixed point (C) u | vedclass

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(C) For the rod $(AB)$ to be in equilibrium,the net force $\overrightarrow{F_{net}}$ and the net torque $\overrightarrow{	au_{net}}$ acting on it mus

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(C) For the rod $(AB)$ to be in equilibrium,the net force $\overrightarrow{F_{net}}$ and the net torque $\overrightarrow{	au_{net}}$ acting on it must be zero.$1$. The forces acting on the rod are: the tension $(T)$ in the rope at point $(A)$,the weight $(Mg)$ acting at the center of mass of the rod,and the normal force $(N)$ from the ice at point $(B)$.$2$. Since the ice is frictionless,the normal force $(N)$ must be vertical.$3$. For the net torque about any point to be zero,the lines of action of all three forces must be concurrent (intersect at a single point) or all be parallel.$4$. The weight $(Mg)$ acts vertically downwards. The normal force $(N)$ acts vertically upwards. For the rod to be in equilibrium,the tension $(T)$ must also act along a line that passes through the intersection of the lines of action of $(Mg)$ and $(N)$.$5$. Since $(Mg)$ and $(N)$ are both vertical,they are parallel. For the rod to be in equilibrium,the tension $(T)$ must also be vertical. This implies that the rope $(AC)$ must be vertical,which is represented in the configuration shown in image $816-$c142.

$A$ rod $(AB)$ is attached to a fixed point $(C)$ using a light rope $(AC)$. The other end of the rod $(B)$ is resting on ice with negligible friction,and the system is in a stationary position. Which of the following can be the equilibrium configuration of this system?

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