A rod is fixed between two points at 20^{circ | vedclass

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(A) The thermal stress developed in a rod fixed between two rigid supports is given by the formula: $	ext{Stress} = Y \alpha \Delta 	heta$. Here,$Y

Vedclass · Accepted Answer

$1.32 	imes 10^7 \, N/m^2$

Vedclass · Answer

(A) The thermal stress developed in a rod fixed between two rigid supports is given by the formula: $	ext{Stress} = Y \alpha \Delta 	heta$. Here,$Y = 1.2 	imes 10^{11} \, N/m^2$ is the Young's modulus,$\alpha = 1.1 	imes 10^{-5} /^{\circ}C$ is the coefficient of linear expansion,and $\Delta 	heta = |20^{\circ}C - 10^{\circ}C| = 10^{\circ}C$ is the change in temperature. Substituting these values into the formula: $	ext{Stress} = (1.2 	imes 10^{11}) 	imes (1.1 	imes 10^{-5}) 	imes 10$. $	ext{Stress} = 1.32 	imes 10^{11} 	imes 10^{-5} 	imes 10^1$. $	ext{Stress} = 1.32 	imes 10^{11-5+1} = 1.32 	imes 10^7 \, N/m^2$.

$A$ rod is fixed between two points at $20^{\circ}C$. The coefficient of linear expansion of the material of the rod is $1.1 \times 10^{-5} /^{\circ}C$ and Young's modulus is $1.2 \times 10^{11} \, N/m^2$. Find the stress developed in the rod if the temperature of the rod becomes $10^{\circ}C$.

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