A satellite while revolving around the earth | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The time taken for one revolution is $t = 1 	ext{ hour } 30 	ext{ minutes} = 90 	ext{ minutes}$.Converting this into seconds: $t = 90 	imes 60

Vedclass · Accepted Answer

$1.16 	imes 10^{-3} 	ext{ rad/s}$

Vedclass · Answer

(A) The time taken for one revolution is $t = 1 	ext{ hour } 30 	ext{ minutes} = 90 	ext{ minutes}$.Converting this into seconds: $t = 90 	imes 60 = 5400 	ext{ s}$.The angle covered in one complete revolution is $	heta = 2\pi 	ext{ radians}$.The formula for angular speed is $\omega = \frac{	heta}{t}$.Substituting the values: $\omega = \frac{2\pi}{5400} = \frac{\pi}{2700} 	ext{ rad/s}$.Calculating the numerical value: $\omega \approx \frac{3.14159}{2700} \approx 1.1635 	imes 10^{-3} 	ext{ rad/s}$.Thus,the angular speed is approximately $1.16 	imes 10^{-3} 	ext{ rad/s}$.

$A$ satellite while revolving around the earth completes one revolution in $1$ hour and $30$ minutes. What is the angular speed of the satellite?

Similar Questions

$A$ boy is whirling a stone tied with a string in a horizontal circular path. If the string breaks,the stone

$(a)$ Name the force that keeps the object moving in a circular path with constant acceleration.
$(b)$ What would happen if this force is absent?

An artificial satellite is moving in a circular orbit of radius nearly $42,250 \, km$. Calculate its linear velocity, if it takes $24 \, \text{hours}$ to revolve around the Earth. (in $ km/s$)

Can a body have constant speed and still be accelerating?

$A$ cyclist goes once around a circular track of diameter $105 \, m$ in $5 \, minutes$. Calculate his speed. (in $m/s$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module