A self-fertilizing trihybrid plant forms: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a plant with $n$ heterozygous gene pairs (trihybrid means $n = 3$):$1$. The number of different types of gametes produced is given by the form

Vedclass · Accepted Answer

$8$ different gametes and $64$ different zygotes

Vedclass · Answer

(C) For a plant with $n$ heterozygous gene pairs (trihybrid means $n = 3$):$1$. The number of different types of gametes produced is given by the formula $2^n$. For a trihybrid,this is $2^3 = 8$ different gametes.$2$. The number of different types of zygotes (genotypes) produced upon self-fertilization is given by the formula $3^n$. For a trihybrid,this is $3^3 = 27$ genotypes. However,in the context of phenotypic combinations or specific genetic outcomes often tested in this format,the total number of possible combinations in a Punnett square is $4^n$. For a trihybrid,this is $4^3 = 64$ different zygotic combinations.$3$. Therefore,the plant forms $8$ different gametes and $64$ different zygotic combinations.

$A$ self-fertilizing trihybrid plant forms:

Similar Questions

$A$ cross between two pea plants,tall with axial flowers and dwarf with terminal flowers,produced offspring that were tall with axial flowers and tall with terminal flowers in the ratio $1:1$. What will be the genotype of the parents?

In the $F_2$ generation of a dihybrid cross of homozygous parents,the number of genotypes and phenotypes will be respectively . . . . . . .

The ratio $1:1:1:1$ is observed in:

Explain the Law of Independent Assortment based on a dihybrid cross.

Which of the following is heterozygous for two pairs of alleles?

Vedclass Test Series

Exam Paper Generator

Online Exam Module