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(C) According to the law of conservation of linear momentum,the total initial momentum of the shell is $0$ because it is initially at rest.After the e

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Move with the same velocity in opposite directions

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(C) According to the law of conservation of linear momentum,the total initial momentum of the shell is $0$ because it is initially at rest.After the explosion,the total momentum must remain $0$.Let the masses of the two pieces be $m_1 = m_2 = m$.Let their velocities be $\vec{v}_1$ and $\vec{v}_2$.By the law of conservation of momentum: $m\vec{v}_1 + m\vec{v}_2 = 0$.This implies $\vec{v}_1 = -\vec{v}_2$.Since the masses are equal,the magnitudes of their velocities must be equal $(|v_1| = |v_2|)$,and the negative sign indicates that they move in exactly opposite directions.

$A$ shell initially at rest explodes into two pieces of equal mass. Then the two pieces will:

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