A shopkeeper sells one transistor for Rs., 84 | vedclass

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(B) Cost Price $(CP)$ of the $1^{	ext{st}}$ transistor $= \frac{840}{1 + 0.20} = \frac{840}{1.2} = Rs.\, 700$ (at $20 \%$ gain).Cost Price $(CP)$ of

Vedclass · Accepted Answer

$5 \frac{15}{17} \% 	ext{ gain}$

Vedclass · Answer

(B) Cost Price $(CP)$ of the $1^{	ext{st}}$ transistor $= \frac{840}{1 + 0.20} = \frac{840}{1.2} = Rs.\, 700$ (at $20 \%$ gain).Cost Price $(CP)$ of the $2^{	ext{nd}}$ transistor $= \frac{960}{1 - 0.04} = \frac{960}{0.96} = Rs.\, 1000$ (at $4 \%$ loss).Total Cost Price $(CP)$ $= 700 + 1000 = Rs.\, 1700$.Total Selling Price $(SP)$ $= 840 + 960 = Rs.\, 1800$.Since $SP > CP$,there is a gain.Gain $= SP - CP = 1800 - 1700 = Rs.\, 100$.Gain percentage $= \left( \frac{	ext{Gain}}{CP} ight) 	imes 100 = \left( \frac{100}{1700} ight) 	imes 100 = \frac{100}{17} = 5 \frac{15}{17} \%$ gain.

$A$ shopkeeper sells one transistor for $Rs.\, 840$ at a gain of $20 \%$ and another for $Rs.\, 960$ at a loss of $4 \%$. His total gain or loss percent is

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