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(C) The electric potential $V$ due to a short electric dipole at a point $(r, 	heta)$ is given by the formula:$V = \frac{1}{4 \pi \epsilon_{0}} \frac

Vedclass · Accepted Answer

$200$

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(C) The electric potential $V$ due to a short electric dipole at a point $(r, 	heta)$ is given by the formula:$V = \frac{1}{4 \pi \epsilon_{0}} \frac{p \cos 	heta}{r^{2}}$Given values:Dipole moment $p = 16 	imes 10^{-9} \, Cm$Distance $r = 0.6 \, m$Angle $	heta = 60^{\circ}$Constant $k = \frac{1}{4 \pi \epsilon_{0}} = 9 	imes 10^{9} \, Nm^{2}/C^{2}$Substituting the values into the formula:$V = \frac{9 	imes 10^{9} 	imes 16 	imes 10^{-9} 	imes \cos(60^{\circ})}{(0.6)^{2}}$Since $\cos(60^{\circ}) = 0.5$:$V = \frac{9 	imes 16 	imes 0.5}{0.36}$$V = \frac{72}{0.36}$$V = 200 \, V$

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