A single slit of width 0.20 , mm is illuminat | vedclass

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(C) The width of the central bright fringe in a single slit diffraction pattern is given by the formula: $\beta = \frac{2 \lambda D}{d}$.Given values

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$4$

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(C) The width of the central bright fringe in a single slit diffraction pattern is given by the formula: $\beta = \frac{2 \lambda D}{d}$.Given values are:Slit width $(d)$ = $0.20 \, mm = 0.20 	imes 10^{-3} \, m$Wavelength $(\lambda)$ = $500 \, nm = 500 	imes 10^{-9} \, m$Distance of screen $(D)$ = $80 \, cm = 80 	imes 10^{-2} \, m$Substituting these values into the formula:$\beta = \frac{2 	imes 500 	imes 10^{-9} 	imes 80 	imes 10^{-2}}{0.20 	imes 10^{-3}}$$\beta = \frac{80000 	imes 10^{-11}}{0.20 	imes 10^{-3}}$$\beta = 4 	imes 10^{-3} \, m = 4 \, mm$.

$A$ single slit of width $0.20 \, mm$ is illuminated with light of wavelength $500 \, nm$. The observing screen is placed $80 \, cm$ from the slit. The width of the central bright fringe will be.....$mm$

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