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(A) For the positive half-cycle of the input voltage,diode $D_1$ becomes forward-biased when the input voltage exceeds $12\ V$. Thus,the output is cli

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Positive peaks of input clipped at $+12\ V$ and negative peaks at $-6\ V$

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(A) For the positive half-cycle of the input voltage,diode $D_1$ becomes forward-biased when the input voltage exceeds $12\ V$. Thus,the output is clipped at $+12\ V$.For the negative half-cycle of the input voltage,diode $D_2$ becomes forward-biased when the input voltage becomes more negative than $-6\ V$ (since the battery is connected with its positive terminal to the ground). Thus,the output is clipped at $-6\ V$.Therefore,the positive peaks are clipped at $+12\ V$ and the negative peaks are clipped at $-6\ V$.

$A$ sinusoidal peak voltage of $15\ V$ is connected between the input terminals of the circuit shown in the figure. Assume the diodes are ideal. In the output waveform,

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