A small block of mass 100,g is tied to a spri | vedclass

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(B) Let the extension in the length of the spring be $x$.The radius of the circular path is $r = 0.2 + x$.The centripetal force required for circular

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$0.75$

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(B) Let the extension in the length of the spring be $x$.The radius of the circular path is $r = 0.2 + x$.The centripetal force required for circular motion is provided by the spring force (tension).$T = m \omega^2 r$$kx = m \omega^2 (0.2 + x)$Given $m = 100\,g = 0.1\,kg$,$k = 7.5\,N/m$,$\omega = 5\,rad/s$,and natural length $l_0 = 0.2\,m$.$7.5x = 0.1 	imes (5)^2 	imes (0.2 + x)$$7.5x = 0.1 	imes 25 	imes (0.2 + x)$$7.5x = 2.5 	imes (0.2 + x)$$7.5x = 0.5 + 2.5x$$5x = 0.5$$x = 0.1\,m$The tension in the spring is $T = kx = 7.5 	imes 0.1 = 0.75\,N$.

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