A small quantity of solution containing Na^{2 | vedclass

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(A) Initial activity $A_0 = 1 \, \mu Ci = 10^{-6} 	imes 3.7 	imes 10^{10} = 3.7 	imes 10^4 \, 	ext{disintegrations/s}$.Activity after $t = 5 \, ho

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(A) Initial activity $A_0 = 1 \, \mu Ci = 10^{-6} 	imes 3.7 	imes 10^{10} = 3.7 	imes 10^4 \, 	ext{disintegrations/s}$.Activity after $t = 5 \, hours$ is $A_t = A_0 e^{-\lambda t}$.Given $e^{-\lambda t} = 0.7927$, the activity of the total blood volume $V$ after $5 \, hours$ is $A_t = A_0 	imes 0.7927 = 3.7 	imes 10^4 	imes 0.7927 = 29330 \, 	ext{disintegrations/s}$.Convert this to disintegrations per minute: $A_t = 29330 	imes 60 = 1,759,800 \, 	ext{disintegrations/min}$.The activity of $1 \, cm^3$ sample is $298 \, 	ext{disintegrations/min}$.Total volume $V = \frac{	ext{Total activity}}{	ext{Activity per } cm^3} = \frac{1,759,800}{298} \approx 5905 \, cm^3$.Since $1000 \, cm^3 = 1 \, L$, the total volume $V \approx 5.9 \, L$.

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