A solenoid of length l metre has self-inducta | vedclass

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(C) The self-inductance $L$ of a solenoid is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $N$ is the number of turns,$A$ is the cross-sectio

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Becomes $4L$ henry

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(C) The self-inductance $L$ of a solenoid is given by the formula $L = \frac{\mu_0 N^2 A}{l}$,where $N$ is the number of turns,$A$ is the cross-sectional area,and $l$ is the length of the solenoid.From this formula,it is clear that the self-inductance $L$ is directly proportional to the square of the number of turns,i.e.,$L \propto N^2$.If the number of turns $N$ is doubled $(N' = 2N)$,the new self-inductance $L'$ will be:$L' \propto (2N)^2 = 4N^2 = 4L$.Therefore,the self-inductance becomes $4L$ henry.

$A$ solenoid of length $l$ metre has self-inductance $L$ henry. If the number of turns is doubled,its self-inductance becomes:

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