(A) Volume of the cone $V_1 = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} \pi (9)^2 (36) = \frac{1}{3} \pi (81) (36) = 972 \pi \, cm^3$.Volume of the cyli

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(A) Volume of the cone $V_1 = \frac{1}{3} \pi r_1^2 h_1 = \frac{1}{3} \pi (9)^2 (36) = \frac{1}{3} \pi (81) (36) = 972 \pi \, cm^3$.Volume of the cylinder $V_2 = \pi r_2^2 h_2 = \pi (9)^2 (9) = 729 \pi \, cm^3$.Volume of material wasted $= V_1 - V_2 = 972 \pi - 729 \pi = 243 \pi \, cm^3$.Percentage of material wasted $= \left( \frac{\text{Volume wasted}}{\text{Original volume}} \right) \times 100 = \left( \frac{243 \pi}{972 \pi} \right) \times 100$.$= \frac{1}{4} \times 100 = 25 \%$.

Competitive Quantitative Aptitude Mensuration Measurement of Volume and Surface Area

Medium

$A$ solid cone of height $36 \, cm$ and radius of base $9 \, cm$ is melted to form a solid cylinder of radius $9 \, cm$ and height $9 \, cm$. What percent of material is wasted in this process (in $\%$)?

A
$25$
B
$0$
C
$5$
D
$10$

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Measurement of Volume and Surface Area

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$A$ solid cone of height $36 \, cm$ and radius of base $9 \, cm$ is melted to form a solid cylinder of radius $9 \, cm$ and height $9 \, cm$. What percent of material is wasted in this process (in $\%$)?

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If the base radius of a cone is increased by $20 \%$ and its slant height is doubled,then by what percentage will the area of its curved surface increase?

$A$ $1 \, m^3$ of metal weighing $90 \, Kg$ is rolled into a square bar $9 \, m$ long. An exact cube is cut off from the bar. How much does it weigh? (in $kg$)

$A$ right prism has a triangular base whose sides are $13\, cm, 20\, cm$ and $21\, cm$. If the altitude of the prism is $9\, cm$,then its volume is......$cm^3$

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