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(C) In a $CCP$ (cubic close packing) arrangement,the number of octahedral voids is equal to the number of atoms,while the number of tetrahedral voids

Vedclass · Accepted Answer

$X_2Z$

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(C) In a $CCP$ (cubic close packing) arrangement,the number of octahedral voids is equal to the number of atoms,while the number of tetrahedral voids is double the number of atoms.Let the number of atoms of $Z$ in the $CCP$ arrangement be $n$.Then,the number of tetrahedral voids is $2n$.Since atoms $X$ occupy all the tetrahedral sites,the number of atoms of $X$ is $2n$.The ratio of atoms $X:Z$ is $2n:n$,which simplifies to $2:1$.Therefore,the formula of the compound is $X_2Z$.

$A$ solid is made of two elements $X$ and $Z$. The atoms $Z$ are in $CCP$ arrangement while the atoms $X$ occupy all the tetrahedral sites. What is the formula of the compound?

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