A solution containing Na_2CO_3 and NaOH requi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the mass of $Na_2CO_3$ be $x \ g$ and $NaOH$ be $y \ g$.Using phenolphthalein indicator,$NaOH$ is completely neutralized and $Na_2CO_3$ is con

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) Let the mass of $Na_2CO_3$ be $x \ g$ and $NaOH$ be $y \ g$.Using phenolphthalein indicator,$NaOH$ is completely neutralized and $Na_2CO_3$ is converted to $NaHCO_3$ (half-neutralization).$Meq. \ of \ NaOH + Meq. \ of \ Na_2CO_3 (half) = 300 	imes 0.1 = 30$.$\frac{y}{40} 	imes 1000 + \frac{x}{106} 	imes 1000 = 30$ ... $(1)$When methyl orange is added,the remaining $NaHCO_3$ is neutralized.$Meq. \ of \ Na_2CO_3 (remaining \ half) = 25 	imes 0.2 = 5$.$\frac{x}{106} 	imes 1000 = 5$ ... $(2)$From $(2)$,$\frac{x}{106} 	imes 1000 = 5$.Substitute this into $(1)$:$\frac{y}{40} 	imes 1000 + 5 = 30$$\frac{y}{40} 	imes 1000 = 25$$y = \frac{25 	imes 40}{1000} = 1 \ g$.

Similar Questions

While titrating a dilute $HCl$ solution with an aqueous $NaOH$ solution,which of the following will not be required?

$3.92 \, g$ of ferrous ammonium sulfate crystals are dissolved in $100 \, mL$ of water. During titration,$20 \, mL$ of this solution is required for complete oxidation by $18 \, mL$ of $KMnO_4$ solution. Calculate the weight of $KMnO_4$ in $1 \, L$ of the solution in grams.

$10.0 \, mL$ of $0.05 \, M \, KMnO_4$ solution was consumed in a titration with $10.0 \, mL$ of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is $..... \times 10^{-2} \, g / L$ (Round off to the nearest integer).

Which reagent is commonly used for the determination of water hardness by titration?

$110 \, mL$ of $0.1 \, N \, HCl$ is titrated with $30 \, mL$ of $0.2 \, N \, NaOH$. The remaining titration is completed by adding $0.25 \, N \, KOH$ solution. What volume of $KOH$ in $mL$ is required?

Vedclass Test Series

Exam Paper Generator

Online Exam Module