A solution containing 10 , g , dm^{-3} of ure | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Two solutions are isotonic if they have the same molar concentration $(C_1 = C_2)$.For urea: Concentration $= \frac{10 \, g \, dm^{-3}}{60 \, g \,

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(B) Two solutions are isotonic if they have the same molar concentration $(C_1 = C_2)$.For urea: Concentration $= \frac{10 \, g \, dm^{-3}}{60 \, g \, mol^{-1}} = \frac{1}{6} \, mol \, dm^{-3}$.For the non-volatile solute: $A$ $5 \%$ solution means $5 \, g$ of solute in $100 \, mL$ of solution,which is equivalent to $50 \, g \, dm^{-3}$.Let the molecular mass of the non-volatile solute be $M$.Concentration of non-volatile solute $= \frac{50 \, g \, dm^{-3}}{M \, g \, mol^{-1}} = \frac{50}{M} \, mol \, dm^{-3}$.Since the solutions are isotonic,$\frac{1}{6} = \frac{50}{M}$.Therefore,$M = 50 	imes 6 = 300 \, g \, mol^{-1}$.

$A$ solution containing $10 \, g \, dm^{-3}$ of urea $(M.wt = 60)$ is isotonic with a $5 \%$ solution of a non-volatile solute. The molecular mass of this non-volatile solute is ......... $g \, mol^{-1}$.

Similar Questions

An unripe mango placed in a concentrated salt solution to prepare pickle,shrivels because . . . . . . .

$0.5 \ N$ solution of $KCl$ is isotonic with $.........$ solution of sugar,assuming $100\%$ dissociation for $KCl$.

If $3 \ g$ of glucose (molar mass $= 180 \ g \ mol^{-1}$) is dissolved in $60 \ g$ of water at $15^{\circ} C$,the osmotic pressure of the solution will be (in $atm$)

What is edema?

In case of osmosis,solvent molecules move from:

Vedclass Test Series

Exam Paper Generator

Online Exam Module