$A$ solution containing $2.675 \ g$ of $CoCl_3 \cdot 6 NH_3$ (molar mass $= 267.5 \ g \ mol^{-1}$) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of $AgNO_3$ to give $4.78 \ g$ of $AgCl$ (molar mass $= 143.5 \ g \ mol^{-1}$). The formula of the complex is
(At. mass of $Ag = 108 \ u$)
(At. mass of $Ag = 108 \ u$)
- A$[Co(NH_3)_6]Cl_3$
- B$[CoCl_2(NH_3)_4]Cl$
- C$[CoCl_3(NH_3)_3]$
- D$[CoCl(NH_3)_5]Cl_2$
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