A solution contains 50 , g of sugar in 350 , | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The concentration of a solution is calculated using the formula:$	ext{Concentration} = \frac{	ext{Mass of solute}}{	ext{Mass of solution}} 	im

Vedclass · Accepted Answer

$12.5$

Vedclass · Answer

(A) The concentration of a solution is calculated using the formula:$	ext{Concentration} = \frac{	ext{Mass of solute}}{	ext{Mass of solution}} 	imes 100$Here,the mass of the solute (sugar) = $50 \, g$.The mass of the solvent (water) = $350 \, g$.The total mass of the solution = $	ext{Mass of solute} + 	ext{Mass of solvent} = 50 \, g + 350 \, g = 400 \, g$.Now,substituting the values into the formula:$	ext{Concentration} = \frac{50}{400} 	imes 100 = \frac{1}{8} 	imes 100 = 12.5 \%$.Thus,the concentration of the solution is $12.5 \%$.

$A$ solution contains $50 \, g$ of sugar in $350 \, g$ of water. Calculate the concentration of the solution in terms of mass by mass percentage of the solution. (in $\%$)

Similar Questions

Describe any three properties of colloids. Categorise the following examples of colloids into different categories of colloids: Jelly,fog,milk,shaving cream.

How are colloids different from suspensions? Identify the colloids from the following: Soda water,milk,sponge,clouds,mixture of alcohol and water,jelly.

Compare in tabular form the properties of true solution and colloids with respect to Tyndall effect and stability.

Which of the following is an aqueous solution?

Colloidal solution appears to be homogeneous but actually it is heterogeneous. Give justification for this statement.

Vedclass Test Series

Exam Paper Generator

Online Exam Module