$A$ solution of $CuSO_4$ is electrolysed for $10 \,min$ with a current of $1.5 \,A$. What is the mass of copper deposited at the cathode (in $,g$)?

  • A
    $0.2938$
  • B
    $0.5876$
  • C
    $0.1469$
  • D
    $0.8814$

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How many grams of cobalt metal will be deposited when a solution of cobalt $(II)$ chloride is electrolyzed with a current of $10 \ A$ for $109$ minutes? ($1 \ Faraday = 96,500 \ C$; Atomic mass of $Co = 59 \ u$)

Which of the following represents the first law of Faraday?

Assertion $(A)$: The charge on one mole of electrons is one Faraday.
Reason $(R)$: The quantity of current required to deposit one mole of $Mg$ from $Mg^{2+}$ electrolyte solution is two Faradays.
The correct answer is

Three electrolytic cells $A, B, C$ containing solutions of $ZnSO_{4}, AgNO_{3}$ and $CuSO_{4}$ respectively are connected in series. $A$ steady current of $1.5 \ A$ was passed through them until $1.45 \ g$ of silver deposited at the cathode of cell $B$. How long did the current flow? What mass of copper and zinc were deposited?

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The number of Faraday required to generate $1$ $g$ $atom$ of $Mg$ from $MgCl_2$ is :-

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