$A$ solution of a salt of a metal was electrolysed for $150$ minutes with a current of $0.15$ amperes. The weight of metal deposited was $0.783 \ g$. The equivalent weight of the metal is ................... $g$. (in $.97$)
- A$55$
- B$65$
- C$75$
- D$85$
Explore More
Similar Questions
What is the number of faraday required to produce $0.18 \ g$ aluminium at cathode during electrolysis of molten $AlCl_3$ (in $F$)? (Molar mass of $Al = 27 \ g \ mol^{-1}$)
On passing $3 \ A$ of electricity for $50 \ minutes$,$1.8 \ g$ of metal deposits. The equivalent mass of the metal is:
Medium
View Solution$A$ steady current of $5 \, A$ is maintained for $45 \, min$. During this time,it deposits $4.572 \, g$ of zinc at the cathode of a voltameter. The $E.C.E.$ of zinc is:
Medium
View SolutionSame amount of electricity is passed through aqueous solutions of $AgNO_3$ and $CuSO_4$. The number of $Ag$ and $Cu$ atoms deposited are $x$ and $y$ respectively. The correct relationship between $x$ and $y$ is
When $1 \ F$ of electricity is passed through acidulated water,the volume of $O_2$ evolved at $STP$ is ............. $dm^{3}$.
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo