A solution of m-chloroaniline,m-chlorophenol | vedclass

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(C) $1$. $m-$chlorobenzoic acid is a strong acid and reacts with $NaHCO_3$ to form a water-soluble salt,which is extracted into fraction $A$.$2$. $m-$

Vedclass · Accepted Answer

$m-$chlorobenzoic acid,$m-$chlorophenol and $m-$chloroaniline

Vedclass · Answer

(C) $1$. $m-$chlorobenzoic acid is a strong acid and reacts with $NaHCO_3$ to form a water-soluble salt,which is extracted into fraction $A$.$2$. $m-$chlorophenol is a weaker acid than $m-$chlorobenzoic acid but stronger than water; it does not react with $NaHCO_3$ but reacts with $NaOH$ to form a water-soluble salt,which is extracted into fraction $B$.$3$. $m-$chloroaniline is a base and does not react with $NaHCO_3$ or $NaOH$. It remains in the organic layer,which is fraction $C$.Therefore,fraction $A$ contains $m-$chlorobenzoic acid,fraction $B$ contains $m-$chlorophenol,and fraction $C$ contains $m-$chloroaniline.

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