(A) The chemical reaction is: $SO_2 + 2H_2S \rightarrow 3S + 2H_2O$. In this reaction,the oxidation state of sulphur in $SO_2$ is $+4$ and it is reduc

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(A) The chemical reaction is: $SO_2 + 2H_2S \rightarrow 3S + 2H_2O$. In this reaction,the oxidation state of sulphur in $SO_2$ is $+4$ and it is reduced to $0$ in $S$. Since $SO_2$ undergoes reduction,it acts as an oxidising agent. $H_2S$ undergoes oxidation (sulphur goes from $-2$ to $0$),so it acts as a reducing agent.