A source and an observer move away from each | vedclass

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(B) According to the Doppler effect,when the source and observer move away from each other,the observed frequency $n'$ is given by the formula:$n' = n

Vedclass · Accepted Answer

$2068$

Vedclass · Answer

(B) According to the Doppler effect,when the source and observer move away from each other,the observed frequency $n'$ is given by the formula:$n' = n \left( \frac{v - v_O}{v + v_S} ight)$Here,$v = 340\; m/s$ is the speed of sound,$v_O = 10\; m/s$ is the velocity of the observer,and $v_S = 10\; m/s$ is the velocity of the source.Given $n' = 1950\; Hz$,we substitute the values:$1950 = n \left( \frac{340 - 10}{340 + 10} ight)$$1950 = n \left( \frac{330}{350} ight)$$1950 = n \left( \frac{33}{35} ight)$$n = 1950 	imes \frac{35}{33} \approx 2068.18\; Hz$Rounding to the nearest whole number,the actual frequency is $2068\; Hz$.

$A$ source and an observer move away from each other with a velocity of $10\; m/s$ with respect to the ground. If the observer finds the frequency of sound coming from the source as $1950\; Hz$,then the actual frequency of the source is .... $Hz$ (velocity of sound in air = $340\; m/s$).

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