A source of sound S having frequency f. Wind | vedclass

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(A) The velocity of sound with respect to the ground is the vector sum of the velocity of sound with respect to the medium and the velocity of the med

Vedclass · Accepted Answer

$\frac{C + u}{f}$

Vedclass · Answer

(A) The velocity of sound with respect to the ground is the vector sum of the velocity of sound with respect to the medium and the velocity of the medium.Since the wind is blowing from the source to the observer,the effective velocity of sound relative to the ground is $v' = C + u$.Because both the source and the observer are at rest,the frequency of the sound detected by the observer remains $f$.The wavelength $\lambda$ is defined as the distance between two consecutive crests,which is given by the ratio of the effective wave speed to the frequency.Using the relation $v' = f 	imes \lambda$,we get $C + u = f \lambda$.Therefore,the wavelength detected by the observer is $\lambda = \frac{C + u}{f}$.

$A$ source of sound $S$ having frequency $f$. Wind is blowing from source to observer $O$ with velocity $u$. If the speed of sound with respect to air is $C$,the wavelength of sound detected by $O$ is:

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