A spring with 10 coils has spring constant k. | vedclass

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(B) The spring constant $k$ of a spring is inversely proportional to its length $l$,i.e.,$k \propto \frac{1}{l}$.This is because the spring constant i

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$2k$

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(B) The spring constant $k$ of a spring is inversely proportional to its length $l$,i.e.,$k \propto \frac{1}{l}$.This is because the spring constant is given by $k = \frac{G J}{R^2 n d^3}$,where $n$ is the number of coils.Since the number of coils $n$ is directly proportional to the length of the spring,we have $k \propto \frac{1}{n}$.When the spring is cut into two equal halves,the number of coils in each new spring becomes $n' = \frac{n}{2} = \frac{10}{2} = 5$.Therefore,the new spring constant $k'$ is given by $k' 	imes n' = k 	imes n$.$k' 	imes \frac{n}{2} = k 	imes n$.$k' = 2k$.

$A$ spring with $10$ coils has spring constant $k$. It is exactly cut into two halves,then each of these new springs will have a spring constant

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