A square coil moves in a plane with uniform v | vedclass

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(C) According to Faraday's law of electromagnetic induction, an induced current is generated only when there is a change in the magnetic flux $(\Phi_B

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Zero

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(C) According to Faraday's law of electromagnetic induction, an induced current is generated only when there is a change in the magnetic flux $(\Phi_B)$ linked with the coil.Magnetic flux is given by $\Phi_B = B \cdot A \cdot \cos(	heta)$, where $A$ is the area of the coil and $	heta$ is the angle between the magnetic field and the area vector.Since the coil is moving with a uniform velocity $v$ in a uniform magnetic field $B$ and the area $A$ remains constant, the magnetic flux $\Phi_B$ linked with the coil does not change over time.Since $\frac{d\Phi_B}{dt} = 0$, the induced electromotive force $(e = -\frac{d\Phi_B}{dt})$ is zero.Therefore, the induced current in the coil is zero.

$A$ square coil moves in a plane with uniform velocity $v$ parallel to its sides. $A$ magnetic field $B$ points perpendicular and into the loop. What is the induced current in the coil?

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