A steel tape gives correct measurement at 20^ | vedclass

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Question

(B) The steel tape is calibrated to be correct at $20^{\circ}C$. When the temperature decreases to $0^{\circ}C$,the steel tape undergoes thermal contr

Vedclass · Accepted Answer

$< 25 \, cm$

Vedclass · Answer

(B) The steel tape is calibrated to be correct at $20^{\circ}C$. When the temperature decreases to $0^{\circ}C$,the steel tape undergoes thermal contraction. Due to contraction,the markings on the tape shift closer together,meaning the distance between the $0$ and $25 \, cm$ marks becomes physically shorter than $25 \, cm$ at $20^{\circ}C$. Since the tape is shorter,it will require more 'tape length' to cover the same physical object. Therefore,a reading of $25 \, cm$ on a contracted tape corresponds to a physical length that is less than $25 \, cm$. Thus,the real length of the wood is less than $25 \, cm$.

$I$ (Fundamental forces in nature)	$II$ (Relative strength)
$(A)$ Strong nuclear force	$(e)$ $10^{-2}$
$(B)$ Weak nuclear force	$(f)$ $1$
$(C)$ Electromagnetic force	$(g)$ $10^{10}$
$(D)$ Gravitational force	$(h)$ $10^{-13}$
	$(i)$ $10^{-39}$

$A$ steel tape gives correct measurement at $20^{\circ}C$. $A$ piece of wood is being measured with the steel tape at $0^{\circ}C$. The reading is $25 \, cm$ on the tape. The real length of the given piece of wood must be:

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