$A$ step-up transformer has a turns ratio of $10:1$. $A$ cell of $e.m.f. = 5 \, V$ is connected to the primary coil. What is the secondary voltage developed?

The primary and secondary coils of a transformer have $50$ and $1500$ turns respectively. If the magnetic flux $\phi = \phi_0 + 4t$,where $\phi$ is in webers,$t$ is time in seconds and $\phi_0$ is a constant,the output voltage across the secondary coil is......$V$

$A$ current of $5 \text{ A}$ is flowing at $220 \text{ V}$ in a primary coil of a transformer. If the voltage produced in the secondary coil is $2200 \text{ V}$ and $50 \%$ of power is lost, then the current in the secondary coil will be (in $\text{ A}$)

$A$ transformer is used to step up an alternating e.m.f. of $220 \ V$ to $4.4 \ kV$ to transmit $6.6 \ kW$ of power. The primary coil has $1000$ turns. The current rating of the secondary coil is (Transformer is ideal): (in $A$)

$A$ step-up transformer has a transformation ratio of $3:2$. What is the voltage in the secondary coil if the voltage in the primary coil is $30\, V$?

In a step-down transformer,the number of turns in: