$A$ straight chain hydrocarbon has the molecular formula $C_8H_{10}$. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $sp^3$,$sp^2$,$sp^2$,$sp^3$,$sp^2$,$sp^2$,$sp$ and $sp$. The structural formula of the hydrocarbon would be

• A
  $CH_3-C\equiv C-CH_2-CH=CH-CH=CH_2$
• B
  $CH_3-CH_2-CH=CH-CH_2-C\equiv C-CH=CH_2$
• C
  $CH_3-CH=CH-CH_2-C\equiv C-CH=CH_2$
• D
  $CH_3-CH=CH-CH_2-CH=CH-C\equiv CH$