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(B) Let the volume of the round bottomed flask be $V$.The initial volume of air inside the flask at $T_{1} = 27^{\circ} C = 300 \, K$ is $V_{1} = V$.A

Vedclass · Accepted Answer

$3/5$

Vedclass · Answer

(B) Let the volume of the round bottomed flask be $V$.The initial volume of air inside the flask at $T_{1} = 27^{\circ} C = 300 \, K$ is $V_{1} = V$.At $T_{2} = 477^{\circ} C = 750 \, K$,the volume of air that would occupy the flask is $V_{2}$.According to Charles's law,at constant pressure,$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$.Substituting the values,$V_{2} = \frac{V 	imes 750}{300} = 2.5 \, V$.The volume of air expelled is the difference between the final volume and the initial volume: $V_{expelled} = 2.5 \, V - V = 1.5 \, V$.The fraction of air expelled is $\frac{V_{expelled}}{V_{initial}} = \frac{1.5 \, V}{2.5 \, V} = \frac{1.5}{2.5} = \frac{3}{5}$.

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