A student multiplied a number by frac{3}{5} i | vedclass

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Question

(D) Let the number be $x$.Correct value $= x 	imes \frac{5}{3} = \frac{5x}{3}$.Incorrect value $= x 	imes \frac{3}{5} = \frac{3x}{5}$.Error $= 	ext

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(D) Let the number be $x$.Correct value $= x 	imes \frac{5}{3} = \frac{5x}{3}$.Incorrect value $= x 	imes \frac{3}{5} = \frac{3x}{5}$.Error $= 	ext{Incorrect value} - 	ext{Correct value} = \frac{3x}{5} - \frac{5x}{3} = \frac{9x - 25x}{15} = -\frac{16x}{15}$.Percentage error $= \frac{	ext{Error}}{	ext{Correct value}} 	imes 100 = \frac{-16x / 15}{5x / 3} 	imes 100$.$= -\frac{16}{15} 	imes \frac{3}{5} 	imes 100 = -\frac{16}{25} 	imes 100 = -64\%$.The magnitude of the percentage error is $64\%$.

$A$ student multiplied a number by $\frac{3}{5}$ instead of $\frac{5}{3}$. What is the percentage error in the calculation?

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