$A$ substance $C_4H_{10}O$ yields on oxidation a compound $C_4H_8O$ which gives an oxime and a positive iodoform test. The original substance on treatment with conc. $H_2SO_4$ gives $C_4H_8$. The structure of the compound is:

  • A
    $CH_3CH_2CH_2CH_2OH$
  • B
    $CH_3CH(OH)CH_2CH_3$
  • C
    $(CH_3)_3COH$
  • D
    $CH_3CH_2-O-CH_2CH_3$

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