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(D) For parallel first-order reactions,the percentage distribution of products is determined by the ratio of their respective rate constants to the to

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$76.83\% \ B$ and $23.17\% \ C$

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(D) For parallel first-order reactions,the percentage distribution of products is determined by the ratio of their respective rate constants to the total rate constant.$\% 	ext{ distribution of } B = \frac{k_1}{k_1 + k_2} 	imes 100$Given $k_1 = 1.26 	imes 10^{-4} \ s^{-1}$ and $k_2 = 0.38 	imes 10^{-4} \ s^{-1}$:$\% 	ext{ of } B = \frac{1.26 	imes 10^{-4}}{1.26 	imes 10^{-4} + 0.38 	imes 10^{-4}} 	imes 100 = \frac{1.26}{1.64} 	imes 100 \approx 76.83\%$$\% 	ext{ of } C = 100 - 76.83\% = 23.17\%$Thus,the percentage distribution is $76.83\% \ B$ and $23.17\% \ C$.

$Experiment$	$[X] / (mol \ L^{-1})$	$[Y] / (mol \ L^{-1})$	$\text{Initial rate} / (mol \ L^{-1} \ min^{-1})$
$I$	$0.1$	$0.1$	$2 \times 10^{-3}$
$II$	$0.2$	$0.2$	$4 \times 10^{-3}$
$III$	$0.4$	$0.4$	$M \times 10^{-3}$
$IV$	$0.1$	$0.2$	$2 \times 10^{-3}$

$A$ substance undergoes first-order decomposition. The decomposition follows two parallel first-order reactions as:
$A \xrightarrow{k_1} B$ $k_1 = 1.26 \times 10^{-4} \ s^{-1}$
$A \xrightarrow{k_2} C$ $k_2 = 3.8 \times 10^{-5} \ s^{-1}$
The percentage distribution of $B$ and $C$ are:

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$A$ substance undergoes first-order decomposition. The decomposition follows two parallel first-order reactions as:$A \xrightarrow{k_1} B$ $k_1 = 1.26 \times 10^{-4} \ s^{-1}$$A \xrightarrow{k_2} C$ $k_2 = 3.8 \times 10^{-5} \ s^{-1}$The percentage distribution of $B$ and $C$ are: