A sum of Rs. 1521 is lent out in two parts in | vedclass

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(D) Let the first part be $x$ and the second part be $(1521 - x)$.Given for the first part: $R_1 = 10\%$,$T_1 = 5 \, yr$.Given for the second part: $R

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$Rs. 936$ and $Rs. 585$

Vedclass · Answer

(D) Let the first part be $x$ and the second part be $(1521 - x)$.Given for the first part: $R_1 = 10\%$,$T_1 = 5 \, yr$.Given for the second part: $R_2 = 8\%$,$T_2 = 10 \, yr$.According to the problem,the simple interest on both parts is equal:$\frac{x 	imes 10 	imes 5}{100} = \frac{(1521 - x) 	imes 8 	imes 10}{100}$$50x = 80(1521 - x)$Divide both sides by $10$:$5x = 8(1521 - x)$$5x = 12168 - 8x$$13x = 12168$$x = \frac{12168}{13} = 936$So,the first part is $Rs. 936$.The second part is $1521 - 936 = Rs. 585$.

$A$ sum of $Rs. 1521$ is lent out in two parts in such a way that the simple interest on one part at $10 \%$ for $5 \,yr$ is equal to that of another part at $8 \%$ for $10 \,yr$. What will be the two parts of the sum?

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