(B) Let the actual total score of the team be $x$.When the best marksman scores $92$ instead of $85$, the total score increases by $(92 - 85) = 7$.The

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(B) Let the actual total score of the team be $x$.When the best marksman scores $92$ instead of $85$, the total score increases by $(92 - 85) = 7$.The new total score becomes $(x + 7)$.The new average is given as $84$ for $8$ persons.Using the formula: $\text{Average} = \frac{\text{Total Sum}}{\text{Number of persons}}$$84 = \frac{x + 7}{8}$$x + 7 = 84 \times 8$$x + 7 = 672$$x = 672 - 7$$x = 665$Therefore, the total points the team actually scored is $665$.

Competitive Quantitative Aptitude Average Average

Medium

$A$ team of $8$ persons participates in a shooting competition. If the best marksman had scored $92$ points instead of $85$ points, the average score for the team would have been $84$. What was the total number of points the team actually scored?

A
$672$
B
$665$
C
$645$
D
$588$

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The average marks of $40$ students in an English exam is $72$. Later,it is found that three marks $64, 62,$ and $84$ were wrongly entered as $68, 65,$ and $73$. The average after the mistakes were rectified is:

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$A$ team of $8$ persons participates in a shooting competition. If the best marksman had scored $92$ points instead of $85$ points, the average score for the team would have been $84$. What was the total number of points the team actually scored?

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