A telephone link operating at a central frequ | vedclass

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(A) The central frequency is $f = 10\, GHz = 10 	imes 10^9\, Hz = 10^{10}\, Hz$.Available bandwidth is $1\%$ of the central frequency:$	ext{Availabl

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$2 	imes 10^4$

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(A) The central frequency is $f = 10\, GHz = 10 	imes 10^9\, Hz = 10^{10}\, Hz$.Available bandwidth is $1\%$ of the central frequency:$	ext{Available Bandwidth} = 1\% 	ext{ of } 10^{10}\, Hz = \frac{1}{100} 	imes 10^{10} = 10^8\, Hz$.The bandwidth required for each telephone channel is $5\, kHz = 5 	imes 10^3\, Hz$.The number of channels that can be accommodated is given by the ratio of the total available bandwidth to the bandwidth per channel:$	ext{Number of channels} = \frac{10^8\, Hz}{5 	imes 10^3\, Hz} = \frac{10^5}{5} = 0.2 	imes 10^5 = 2 	imes 10^4$.

$A$ telephone link operating at a central frequency of $10\, GHz$ is established. If $1\%$ of this is available,then how many telephone channels can be simultaneously provided,given that each telephone covers a bandwidth of $5\, kHz$?

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