A telephonic communication service is working | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total bandwidth available for transmission is $10\%$ of the carrier frequency.Total available bandwidth $= 10\% 	ext{ of } 10 \ GHz = 0.10

Vedclass · Accepted Answer

$2 	imes 10^5$

Vedclass · Answer

(B) The total bandwidth available for transmission is $10\%$ of the carrier frequency.Total available bandwidth $= 10\% 	ext{ of } 10 \ GHz = 0.10 	imes 10 	imes 10^9 \ Hz = 10^9 \ Hz$.Let $n$ be the number of telephonic channels that can be transmitted simultaneously.Each channel requires a bandwidth of $5 \ kHz = 5 	imes 10^3 \ Hz$.The total bandwidth used by $n$ channels is $n 	imes 5 	imes 10^3 \ Hz$.Equating the total available bandwidth to the bandwidth required by $n$ channels:$n 	imes 5 	imes 10^3 = 10^9$$n = \frac{10^9}{5 	imes 10^3} = \frac{10^6}{5} = 0.2 	imes 10^6 = 2 	imes 10^5$.Therefore,$2 	imes 10^5$ telephonic channels can be transmitted simultaneously.

$A$ telephonic communication service is working at a carrier frequency of $10 \ GHz$. Only $10\%$ of it is utilized for transmission. How many telephonic channels can be transmitted simultaneously if each channel requires a bandwidth of $5 \ kHz$?

Similar Questions

The characteristic impedance of a coaxial cable is typically in the range of ..........

Which of the following is not a basic component of a communication system?

$A$ modulated signal is given by $C_m(t) = A_c \sin \omega_c t + \mu A_c \sin \omega_m t \sin \omega_c t$,where $\mu$ is the modulation index. To keep the signal without distortion,the value of $\mu$ should be

For efficient transmission of sound waves of wavelength $\lambda$,the minimum length of the antenna should be.....

Radio waves that reach the receiver after being reflected from the ionosphere propagate via .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module