A thin hollow copper pipe carries a direct cu | vedclass

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(D) For a thin hollow copper pipe carrying a steady direct current $(I)$:$1$. According to Ampere's Circuital Law, the magnetic field inside a hollow

Vedclass · Accepted Answer

Electric field outside the pipe is not zero.

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(D) For a thin hollow copper pipe carrying a steady direct current $(I)$:$1$. According to Ampere's Circuital Law, the magnetic field inside a hollow conductor is zero because the enclosed current is zero.$2$. Outside the pipe, the magnetic field is given by $B = \frac{\mu_0 I}{2 \pi r}$, which is not zero.$3$. For a current-carrying conductor, there is a potential gradient along the length of the pipe to maintain the current. This implies an electric field exists along the surface and inside the conductor.$4$. However, outside the pipe, in the surrounding space, the electric field is zero because the pipe is electrically neutral (it carries a current, not a net static charge).$5$. Therefore, the statement that the electric field outside the pipe is not zero is incorrect.

$A$ thin hollow copper pipe carries a direct current. Which of the following statements is incorrect?

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