A thin prism P_1 with angle 4^o and made from | vedclass

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(C) The deviation produced by a thin prism of prism angle $A$ is given by $\delta = (\mu - 1) A$.Since the combined prism produces dispersion without

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(C) The deviation produced by a thin prism of prism angle $A$ is given by $\delta = (\mu - 1) A$.Since the combined prism produces dispersion without deviation,the total deviation is zero.$\delta = \delta_1 + \delta_2 = 0$$(\mu_1 - 1) A_1 + (\mu_2 - 1) A_2 = 0$$(\mu_1 - 1) A_1 = -(\mu_2 - 1) A_2$The negative sign indicates that the refracting angles of the two prisms are in opposite directions.$A_2 = \frac{(\mu_1 - 1) A_1}{(\mu_2 - 1)} = \frac{(1.54 - 1) 	imes 4^o}{(1.72 - 1)}$$A_2 = \frac{0.54 	imes 4^o}{0.72} = \frac{3}{4} 	imes 4^o = 3^o$

$A$ thin prism $P_1$ with angle $4^o$ and made from glass of refractive index $1.54$ is combined with another prism $P_2$ made from glass of refractive index $1.72$ to produce dispersion without deviation. The angle of prism $P_2$ is......$^o$

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