A thin prism having refracting angle 10^{circ | vedclass

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(A) The condition for dispersion without deviation is given by the formula for net deviation $\delta = (\mu - 1)A + (\mu' - 1)A' = 0$.Since the prisms

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(A) The condition for dispersion without deviation is given by the formula for net deviation $\delta = (\mu - 1)A + (\mu' - 1)A' = 0$.Since the prisms are combined to produce dispersion without deviation,the net deviation must be zero,meaning the prisms must be placed in opposite orientations.Thus,the condition is $(\mu - 1)A = (\mu' - 1)A'$.Given values are $\mu = 1.42$,$A = 10^{\circ}$,and $\mu' = 1.7$.Substituting these values into the equation:$(1.42 - 1) 	imes 10^{\circ} = (1.7 - 1) 	imes A'$$0.42 	imes 10^{\circ} = 0.7 	imes A'$$4.2^{\circ} = 0.7 	imes A'$$A' = \frac{4.2}{0.7} = 6^{\circ}$.Therefore,the refracting angle of the second prism is $6^{\circ}$.

$A$ thin prism having refracting angle $10^{\circ}$ is made of glass of refractive index $1.42$. This prism is combined with another thin prism of glass of refractive index $1.7$. This combination produces dispersion without deviation. The refracting angle of the second prism should be....$^{\circ}$

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