A thin prism of angle 6^{circ} and refractive | vedclass

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(B) For a thin prism,the average deviation is given by $\delta = A(n_{Y} - 1)$.Since the two prisms are combined to produce no dispersion,they are pla

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$4$

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(B) For a thin prism,the average deviation is given by $\delta = A(n_{Y} - 1)$.Since the two prisms are combined to produce no dispersion,they are placed in opposition to each other.The net average deviation $\delta$ is given by the difference in deviations produced by the two prisms:$\delta = A_{1}(n_{Y1} - 1) - A_{2}(n_{Y2} - 1)$Given $A_{1} = 6^{\circ}$,$n_{Y1} = 1.5$ and $A_{2} = 5^{\circ}$,$n_{Y2} = 1.55$.$\delta = 6(1.5 - 1) - 5(1.55 - 1)$$\delta = 6(0.5) - 5(0.55)$$\delta = 3.0 - 2.75 = 0.25^{\circ}$We are given $\delta = (\frac{1}{x})^{\circ}$,so $\frac{1}{x} = 0.25 = \frac{1}{4}$.Therefore,$x = 4$.

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