$A$ thin rod of length $L$ is bent to form a semicircle. The mass of the rod is $M$. What will be the gravitational potential at the centre of the circle?

  • A
    $ - \frac{GM}{L} $
  • B
    $ - \frac{GM}{2\pi L} $
  • C
    $ - \frac{\pi GM}{2L} $
  • D
    $ - \frac{\pi GM}{L} $

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At $527 \, ^oC$,the reaction given below has $K_c = 4$:
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The major product of the following reaction is

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