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(C) For a uniformly charged thin spherical shell of radius $R$ and charge $q$,the electric potential at any point inside the shell (including the cent

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(C) For a uniformly charged thin spherical shell of radius $R$ and charge $q$,the electric potential at any point inside the shell (including the center) is constant and equal to the potential at the surface.The potential at any point $r \leq R$ is given by $V = \frac{1}{4 \pi \varepsilon_0} \frac{q}{R}$.Since point $C$ is at the center $(r = 0)$ and point $P$ is on the surface $(r = R)$,both points are at the same potential.Therefore,$V_C = V_P = \frac{1}{4 \pi \varepsilon_0} \frac{q}{R}$.The potential difference between points $C$ and $P$ is $V_C - V_P = 0$.

$A$ thin spherical shell is charged by some source. The potential difference between the two points $C$ (the center) and $P$ (a point on the surface) as shown in the figure is: (Take $\frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \text{ SI units}$)

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