A tin chloride Q undergoes the following reac | vedclass

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(C) $Q$ is $SnCl_2$.$1. SnCl_2 + Cl^{-} \rightarrow [SnCl_3]^{-} (X)$. The $Sn$ atom in $[SnCl_3]^{-}$ has $3$ bond pairs and $1$ lone pair,so it is $

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$1, 4$

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(C) $Q$ is $SnCl_2$.$1. SnCl_2 + Cl^{-} \rightarrow [SnCl_3]^{-} (X)$. The $Sn$ atom in $[SnCl_3]^{-}$ has $3$ bond pairs and $1$ lone pair,so it is $sp^3$ hybridized with pyramidal geometry. Statement $(1)$ is correct.$2. SnCl_2 + Me_3N \rightarrow SnCl_2 \cdot NMe_3 (Y)$. This is an adduct where $N$ donates a lone pair to $Sn$,forming a coordinate bond. Statement $(4)$ is correct.$3. SnCl_2 + 2CuCl_2 \rightarrow SnCl_4 (Z) + 2CuCl$. The oxidation state of $Sn$ in $SnCl_4$ is $+4$. Statement $(2)$ is incorrect.$4. SnCl_4$ has $4$ bond pairs and $0$ lone pairs. Statement $(3)$ is incorrect.Therefore,statements $(1)$ and $(4)$ are correct.

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