A tiny 0.50, g ball carries a charge of magni | vedclass

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(B) Given:Mass $m = 0.50\, g = 0.50 	imes 10^{-3}\, kg = 5 	imes 10^{-4}\, kg$Charge $q = 10\, \mu C = 10 	imes 10^{-6}\, C = 10^{-5}\, C$Electric

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$8 	imes 10^{-3}\,N$

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(B) Given:Mass $m = 0.50\, g = 0.50 	imes 10^{-3}\, kg = 5 	imes 10^{-4}\, kg$Charge $q = 10\, \mu C = 10 	imes 10^{-6}\, C = 10^{-5}\, C$Electric field $E = 300\, N/C$ (downward)Gravity $g = 10\, m/s^2$ (approx)Since the charge is positive,the electric force $F_e = qE$ acts in the direction of the electric field (downward).The forces acting on the ball are:$1$. Weight $W = mg$ (downward)$2$. Electric force $F_e = qE$ (downward)$3$. Tension $T$ (upward)For equilibrium,$T = mg + qE$$T = (5 	imes 10^{-4} 	imes 10) + (10^{-5} 	imes 300)$$T = 5 	imes 10^{-3} + 3 	imes 10^{-3}$$T = 8 	imes 10^{-3}\, N$

$A$ tiny $0.50\, g$ ball carries a charge of magnitude $10\, \mu C$. It is suspended by a thread in a downward electric field of intensity $300\, N/C$. If the charge on the ball is positive,then the tension in the string is

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