A tobacco plant which is heterozygous for alb | vedclass

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(B) The tobacco plant is heterozygous for albinism,so its genotype is $Aa$.Self-pollination of the heterozygous plant $(Aa 	imes Aa)$ results in the

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$600$

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(B) The tobacco plant is heterozygous for albinism,so its genotype is $Aa$.Self-pollination of the heterozygous plant $(Aa 	imes Aa)$ results in the following $F_1$ generation genotypes:$AA$ (homozygous dominant),$Aa$ (heterozygous),$Aa$ (heterozygous),and $aa$ (homozygous recessive).The ratio of genotypes is $1:2:1$.The parental genotype is $Aa$,which accounts for $2$ out of $4$ parts,or $50\%$ of the total offspring.Therefore,out of $1200$ seedlings,the number of seedlings with the parental genotype is $1200 	imes 0.5 = 600$.

$A$ tobacco plant which is heterozygous for albinism ($a$ recessive character) is self-pollinated. If $1200$ seeds are subsequently germinated,how many of the seedlings would have the parental genotype?

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